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How do you solve this life table? numbers for life table analysis

X Sx Mx lx mxlx xmlx
stage survival fecundity survivorship
1 0.95 0 1
2 0.99 0
3 0.99 0
4 0.95 0
5 0.9 0
6. 0.9 0.5
7 0.9 1
8 0.8 1
9 0.5 0.5
10 0 0
11 0 0

asked
User Vkinra
by
7.7k points

1 Answer

7 votes

Answer:

Step-by-step explanation:

To solve the life table and calculate the required values, we'll use the given information. The life table contains the following columns:

  • X: Age or stage
  • Sx: Survival rate from age X to X+1
  • Mx: Fecundity (average number of offspring produced) at age X
  • lx: Number of individuals alive at age X (also called survivorship)
  • mxlx: Number of offspring produced at age X (lx multiplied by Mx)
  • xmlx: Number of individuals alive at age X+1 (lx multiplied by Sx)

We'll start by calculating lx (number of individuals alive at each stage):

Age (X) lx

1 1

2 ?

3 ?

4 ?

5 ?

6 ?

7 ?

8 ?

9 ?

10 ?

11 ?

For age 2, the number of individuals alive (lx) can be calculated by multiplying the survival rate (Sx) from age 1 to 2 (0.95) with the number of individuals alive at age 1 (lx = 1):

lx(2) = Sx(1 to 2) * lx(1) = 0.95 * 1 = 0.95

Similarly, we can calculate lx for the remaining ages:

Age (X) lx

1 1

2 0.95

3 ?

4 ?

5 ?

6 ?

7 ?

8 ?

9 ?

10 ?

11 ?

Next, we can calculate mxlx (number of offspring produced at each stage):

Age (X) lx Mx mxlx

1 1 0 0

2 0.95 0 0

3 ? ? ?

4 ? ? ?

5 ? ? ?

6 ? ? ?

7 ? ? ?

8 ? ? ?

9 ? ? ?

10 ? ? ?

11 ? ? ?

Given that there is no fecundity (Mx = 0) for all ages, mxlx will be 0 for all ages.

Age (X) lx Mx mxlx

1 1 0 0

2 0.95 0 0

3 ? 0 0

4 ? 0 0

5 ? 0 0

6 ? 0 0

7 ? 0 0

8 ? 0 0

9 ? 0 0

10 ? 0 0

11 ? 0 0

Finally, we can calculate the number of individuals alive at the next stage (xmlx) using the survival rate (Sx):

Age (X) lx Mx mxlx Sx xmlx

1 1 0 0 - -

2 0.95 0 0 - -

3 ? 0 0 ? ?

4 ? 0 0 ? ?

5 ? 0 0 ? ?

6 ? 0 0 ? ?

7 ? 0 0 ? ?

8 ? 0 0 ? ?

9 ? 0 0 ? ?

10 ? 0 0 ? ?

11 ? 0 0 ? ?

Using the survival rates (Sx) provided, we can calculate the number of individuals alive at the next stage (xmlx) for each age:

xmlx(3) = Sx(2 to 3) * lx(2) = 0.99 * 0.95 = 0.9405

Similarly, we can calculate xmlx for the remaining ages:

Age (X) lx Mx mxlx Sx xmlx

1 1 0 0 - -

2 0.95 0 0 - -

3 0.95 0 0 0.99 0.9405

4 ? 0 0 ? ?

5 ? 0 0 ? ?

6 ? 0 0 ? ?

7 ? 0 0 ? ?

8 ? 0 0 ? ?

9 ? 0 0 ? ?

10 ? 0 0 ? ?

11 ? 0 0 ? ?

Repeat the same process to calculate the remaining values until you have filled in all the values in the table.

answered
User AnAgent
by
8.6k points
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