Explanation:
To find the value(s) for x such that f(x) = 23, we can set up the equation:
x^2 - 4x + 2 = 23
To solve this quadratic equation, we need to rearrange it into the standard quadratic form:
x^2 - 4x - 21 = 0
Now, we can solve this equation by factoring, completing the square, or using the quadratic formula. In this case, let's use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For the equation x^2 - 4x - 21 = 0, the coefficients are: a = 1, b = -4, and c = -21.
Plugging these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)^2 - 4(1)(-21))) / (2(1))
x = (4 ± √(16 + 84)) / 2
x = (4 ± √100) / 2
x = (4 ± 10) / 2
Now, we have two solutions:
x = (4 + 10) / 2 = 14 / 2 = 7
x = (4 - 10) / 2 = -6 / 2 = -3
Therefore, the values for x such that f(x) = 23 are x = 7 and x = -3.