Question

a charge of 1.5 x 106 c and a charge of 3.2 x 10 4 c is separated by 1.5 m. what is the force between the two charges?

Answer 1

1.92 × 10²⁰ N

Step-by-step explanation:

To calculate the force acting between two charges, we have to use the following formula:

`\boxed{F = (1)/(4\pi \epsilon _0)(Q_1Q_2)/(r^2)}`

where:

• F ⇒ force

• ε₀ ⇒ permittivity of free space = 8.85 × 10⁻¹² F/m

• Q₁, Q₂ ⇒ magnitude of the charges = 1.5 × 10⁶ C, 3.2 × 10⁴ C

• r ⇒ distance between the charges = 1.5 m

Substituting the given data into the formula above, we get:

`F = (1)/(4\pi * 8.85 * 10^(-12)) * (1.5 * 10^(6) * 3.2 * 10^4)/((1.5)^2)`

⇒ F = 1.92 × 10²⁰ N