asked 22.6k views
0 votes
Evaluate x^y, when x=-2 and y=3

asked
User Norswap
by
7.0k points

2 Answers

2 votes

The answer is:

-8

Step-by-step explanation:

Plug in the value of each variable.


\sf{x^y}


\sf{-2^3}

Multiply -2 by itself 3 times. Remember, the exponent tells us how many times the base should be multiplied by itself:


\sf{-8}

Hence, the answer is -8.

answered
User NeilCrosby
by
7.9k points
2 votes

Answer:

- 8

Step-by-step explanation:

given


x^(y) ( substitute x = - 2 and y = 3 )

=
(-2)^(3)

= - 2 × - 2 × - 2

= 4 × - 2

= - 8

answered
User Makboney
by
7.8k points

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