64^2x+1 +8^2x=104 {64}^(2x + 1) + {8}^(2x) = 104 ​

Question

64^2x+1 +8^2x=104

`{64}^(2x + 1) + {8}^(2x) = 104`
​

Answer 1

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x

=

103

4160

Decimal Form:

x

=

0.02475961

…

Explanation: