Question

Show the printout of the following code as well as illustration

of I and J value for each loop evaluation expression points
(draw the variable state table).
int main()
{
int i = 1;
while (i <= 4)
{

Answer 1

Certainly! Here's the modified code with the loop continuation and variable state table:

```c

#include <stdio.h>

int main() {

int i = 1;

while (i <= 4) {

int j = i;

while (j >= 1) {

printf("i = %d, j = %d\\", i, j);

j--;

}

i++;

}

return 0;

}

```

The output of the code will be as follows:

```

i = 1, j = 1

i = 2, j = 2

i = 2, j = 1

i = 3, j = 3

i = 3, j = 2

i = 3, j = 1

i = 4, j = 4

i = 4, j = 3

i = 4, j = 2

i = 4, j = 1

```

Here's the variable state table that illustrates the values of `i` and `j` for each loop evaluation:

```

-------------------------------------

| i | j | Loop Level |

-------------------------------------

| 1 | 1 | j |

| 2 | 2 | j |

| 2 | 1 | j |

| 3 | 3 | j |

| 3 | 2 | j |

| 3 | 1 | j |

| 4 | 4 | j |

| 4 | 3 | j |

| 4 | 2 | j |

| 4 | 1 | j |

-------------------------------------

```

In each iteration of the outer `while` loop, the variable `i` increases by 1. In each iteration of the inner `while` loop, the variable `j` starts with the same value as `i` and decreases by 1 until it reaches 1. The process repeats until `i` reaches 4, resulting in the displayed output and variable state table.

Step-by-step explanation:

FROM Phillipines