Answer:
To find the pressure at which the solubility of the gas would be 0.2 g/L, we can use the concept of Henry's Law. Henry's Law states that the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid.
The equation for Henry's Law is:
S = k * P
Where:
S is the solubility of the gas in the liquid (in g/L)
k is the Henry's Law constant (which depends on the specific gas and liquid)
P is the partial pressure of the gas above the liquid (in atm)
We can set up a proportion to find the unknown pressure (P2) when the solubility (S2) is 0.2 g/L:
S1 / P1 = S2 / P2
Substituting the given values:
0.028 g/L / 3.5 atm = 0.2 g/L / P2
Now we can solve for P2:
P2 = (0.2 g/L * 3.5 atm) / 0.028 g/L
P2 = 24.5 atm
Therefore, at a pressure of 24.5 atm, the solubility of the gas would be 0.2 g/L.