Question

A skier moves at a constant speed down a slope with an angle of θ= 27 ∘ . [ θ is the angle between the horizontal and the ski slope.]. Air resistance may be ignored in this problem. Which of the options below describes the net force in the direction perpendicular to the slope? (Take the direction perpendicular to the slope and (partially)upwards to be positive) Constants| Periodic Table A skier moves at a constant speed down a slope with an angle of θ-270-e is the angle between the horizontal and the ski slope.]. Air resistance may be ignored in this problem O N-mgcos(e) N-mg sin(θ) O mgsin(0) HN Submit Request Answer Part C What is the value of the net force perpendicular to the slope? View Available Hint(s) Perpendicular F net SubmitPr Previous Answe X Incorrect; Try Again; 5 attempts remaining Part D This question will be shown after you complete previous question(s) Part E This question will be shown after you complete

Answer 1

The net force perpendicular to the slope is zero because there is no acceleration in that direction. The normal force is equal in magnitude to the component of weight perpendicular to the slope, balancing out the forces.

Step-by-step explanation:

The net force in the direction perpendicular to the slope is zero. This is because there is no acceleration in this direction, therefore the forces perpendicular to the slope add up to zero. The skier's weight has a component parallel to the slope (Wx) and a component perpendicular to the slope (Wy). Since there is no motion perpendicular to the slope, the normal force (N) is equal in magnitude to Wy, balancing out the component of weight.