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Limn→[infinity]​n1​∑i=1n​ni​ is (A) 1 (B) 2 (C) 1/2 (D) e (E) 1/3

Limn→[infinity]​n1​∑i=1n​ni​ is (A) 1 (B) 2 (C) 1/2 (D) e (E) 1/3
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Limn→[infinity]​n1​∑i=1n​ni​ is (A) 1 (B) 2 (C) 1/2 (D) e (E) 1/3

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User Vtortola
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4 votes

Answer:

A

Explanation:

answered
User Anirudha
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