asked 233k views
3 votes
What is the answer of
(-8)^0 - 11^0/(-2/3)^0​

asked
User Wjamyers
by
7.1k points

2 Answers

4 votes

Answer:

The answer is 0

(-8)^0 - 11^0/(-2/3)^0​ = 0

Explanation:

We note that anything to the power of 0 is 1,

or,


a^0 =1\\

Hence,


(-8)^0=1\\11^0=1\\(-2/3)^0=1

Putting these values in the problem, we get,

1 - (1)/(1)

1-1

= 0

so,

(-8)^0 - 11^0/(-2/3)^0​ = 1 - 1 = 0

answered
User Ferdane
by
8.1k points
6 votes

The answer is:

0

Work/explanation:

Using the exponent law:


\bullet\qquad\sf{x^0=1}

So any number raised to the power of 0 is equal to 1.

Now, let's apply the property to this problem.


\sf{(-8)^0=1}


\sf{1-11^0/(-2/3)^0}


\sf{1-1/1}


\sf{1-1}


\bf{0}

Therefore, the answer is 0.

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