Step-by-step explanation:
Here's the conversion of the given C code blocks into assembly code, assuming the variables are stored in the specified registers:
a.
```assembly
li $r0, 1 # a = 1
li $r1, 6 # b = 6
add $r2, $r0, $r1 # c = a + b
sub $r0, $r0, $r2 # a = a - c
addi $r2, $r2, 1 # c++
sll $r0, $r0, 3 # a <<= 3
```
b.
```assembly
slt $r3, $r0, $r1 # if (a < b)
beqz $r3, else_label # jump to else_label if a >= b
add $r0, $r0, $r2 # a + c
j end_label # jump to end_label
else_label:
sub $r0, $r0, $r2 # a - c
end_label:
```
c.
```assembly
li $r3, 10 # x = 10
loop:
bgtz $r3, loop_end # exit loop if x <= 0
add $r2, $r2, $r3 # C = C + x
add $r0, $r0, $r2 # a = a + C
add $r1, $r0, $r3 # b = a + x
subi $r3, $r3, 1 # x--
j loop # jump to loop
loop_end:
```
d.
```assembly
slt $r3, $r0, 2 # if (a < 2)
beqz $r3, else_label # jump to else_label if a >= 2
slt $r3, $r0, $r1 # if (a >= b)
bnez $r3, else_label # jump to else_label if a < b
sub $r0, $r0, $r2 # a = b
j end_label # jump to end_label
else_label:
addi $r0, $r0, 2 # a += 2
end_label:
```
In the above assembly code, the instructions assume that the register `$r0` corresponds to variable `a`, `$r1` corresponds to variable `b`, and `$r2` corresponds to variable `c`. The register `$r3` is used for temporary operations or loop variables.