Answer:
Step-by-step explanation:
For the given rate law, Rate = k [ClO_3^-][I^-][H^+]^2, the units of the rate constant (k) can be determined by examining the units of each reactant concentration and the overall rate.
The concentration of ClO_3^- is given in moles per liter (mol/L).
The concentration of I^- is given in moles per liter (mol/L).
The concentration of H^+ is given in moles per liter (mol/L).
The overall rate is given in moles per liter per second (mol/L·s).
By comparing the units, we can determine the units of k:
Rate = k [ClO_3^-][I^-][H^+]^2
mol/(L·s) = k (mol/L)(mol/L)(mol/L)^2
Simplifying the units, we get:
mol/(L·s) = k mol^3/(L^3)
Therefore, the units of k are: mol^2/(L^2·s)
The correct answer is C) mol^2/(L^2·s).
For the second question, if a reaction is second-order in a reactant and the concentration of that reactant is decreased by a factor of 2, the reaction rate will decrease by a factor of 1/2.
The correct answer is C) decrease by a factor of 1/2.
For the third question, if the initial concentration of H_2SeO_3 is tripled while holding the initial concentrations of H^+ and I^- constant, the rate of the reaction will increase by a factor of 2 (doubling).
The correct answer is B) 2.