Question

A particle is moving uniformly in a circle with radius 50 cm. The linear speed of the particle is 60 cm/s. The acceleration of the particle has a magnitude of O 72 cm/s2 O 36 m/s2 O 3.6 m/s2 zero. 1.8 * 105 cm/s2

Answer 1

The acceleration of the particle moving uniformly in a circle with a radius of 50 cm and a linear speed of 60 cm/s is 72 cm/s2.

Step-by-step explanation:

The acceleration of the particle moving uniformly in a circle with a radius of 50 cm and a linear speed of 60 cm/s can be calculated using the formula:

ac = v2 / r,

where ac is the centripetal acceleration, v is the linear speed, and r is the radius of the circle. Substituting the given values:

ac = (60 cm/s)^2 / 50 cm = 72 cm/s2.

Therefore, the acceleration of the particle has a magnitude of 72 cm/s2.

Answer 2

The particle moving uniformly in a circle with a radius of 50 cm and a linear speed of 60 cm/s has a centripetal acceleration of 72 cm/s².

Step-by-step explanation:

The subject of this question is Physics, specifically relating to the topic of uniform circular motion and centripetal acceleration. A particle is moving in a circular path with a constant linear speed, which means it experiences centripetal acceleration directed towards the center of the circle. The magnitude of this acceleration is determined by the formula a = v²/r, where v is the linear speed and r is the radius of the circle. Given the linear speed of 60 cm/s and a radius of 50 cm, the acceleration can be calculated.

Using the formula a = v²/r, we substitute the values to get:
a = (60 cm/s)² / (50 cm)
a = 3600 cm²/s² / 50 cm
a = 72 cm/s².
Therefore, the magnitude of the particle's acceleration is 72 cm/s².