A 1.00-l sample of a gas at stp has a mass of 0.759 g. the molar mass of the gas is

Question

asked May 18, 2024 51.1k views

1 Answer

Borisu · Answer 1 · 2024-05-23T20:49:11+0000

Answer:

17 g/mol

Step-by-step explanation:

(.759*.0821 *273)/(1*1) = 17

PV = nRT

molar mass = (grams * RT)/PV

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