Question

There are two numbers that have a sum of 47. Three times the lesser

number is equal to 9 more than the greater number. What are the
numbers?

Answer 1

• The numbers are 14 and 33

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Let the numbers be s and l.

We are given that:

• Sum of the two is 47 and 3 times the lesser number is equal to 9 more than the greater number.

Set up equations:

• s + l = 47
• 3s = l + 9

Eliminate l:

• l = 47 - s and
• l = 3s - 9

Solve for s:

• 47 - s = 3s - 9
• 3s + s = 47 + 9
• 4s = 56
• s = 14

Find l:

• l = 47 - 14
• l = 33