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How many grams of AuCl3 contain 5.0 x 1023 molecules?

How many grams of AuCl3 contain 5.0 x 1023 molecules?
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How many grams of AuCl3 contain 5.0 x 1023 molecules?

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User Fresko
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Answer:

approximately 251.55 grams of AuCl3 would contain 5.0 x 10^23 molecules.

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User Ken Tan
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