Answer:
1. 108.8 ft per second
Explanation:
1. If a bowling ball is dropped out of an airplane, its speed after 3.4 seconds, assuming no air resistance, can be calculated using the equation v = 32t, where v is the velocity in feet per second and t is the time in seconds. Plugging in t = 3.4 seconds, we get:
v = 32 x 3.4
v = 108.8 feet per second
Therefore, the velocity of the bowling ball after 3.4 seconds, assuming no air resistance, is 108.8 feet per second.