Question

According to the following reaction, how many moles of sodium

chloride will be formed upon the complete reaction of 0.511 moles
chlorine gas with excess sodium iodide?
Cl2 (g) + 2NaI (s) -> 2NaCl (

Answer 1

1.022 mol of sodium chloride

Step-by-step explanation:

1 mol of cl = 2mol of Nacl

0.511mol = x

=2 × 0.511

= 1.022 mol