For Problem 2, you can see its law of syllogism
which is:
p -> q,
q -> r
p -> r
p v q = p OR q,
p n q = p AND q (n is the v upside down)
so you need to give an example of how
p -> (q AND r) can be equal to (NOT p, OR q) and (NOT p, OR r)
just find 3 expressions or sentences that can plug into p q and r, and there you have it :)