Question

How many moles of hydrogen will form if 3.0 mole of potassium metal reacts completely with hydrochloric acid?

Answer 1

If 3.0 moles of potassium metal react with hydrochloric acid, 1.5 moles of hydrogen gas will be produced based on the stoichiometry of the reaction.

Step-by-step explanation:

When potassium metal reacts completely with hydrochloric acid, hydrogen gas is produced according to the following balanced chemical equation:

2 K (s) + 2 HCl (aq) → 2 KCl (aq) + H₂ (g)

From the equation, we see that 2 moles of potassium (K) produce 1 mole of hydrogen (H₂). Therefore, to determine how many moles of hydrogen will form when 3.0 moles of potassium reacts, we can set up a ratio:

(3.0 moles K) × (1 mole H₂ / 2 moles K) = 1.5 moles H₂

Thus, 1.5 moles of hydrogen will form if 3.0 moles of potassium metal reacts completely with hydrochloric acid.

Answer 2

1.5 moles of hydrogen will form if 3.0 mole of potassium metal reacts completely with hydrochloric acid.

Step-by-step explanation:

The balanced chemical equation for the reaction of potassium metal with hydrochloric acid is:

2K(s) + 2HCl(aq) → 2KCl(aq) + H2(g)

As per the above equation, 2 moles of potassium reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

So, for 3.0 moles of potassium metal react with hydrochloric acid, we can say that it will produce 3.0/2 = 1.5 moles of hydrogen gas.

Therefore, 1.5 moles of hydrogen will form if 3.0 mole of potassium metal reacts completely with hydrochloric acid.