Question

A ball rolls of a table that 1.2 meter above the ground.

how much time does it take for the ball to hit the ground
how far from the table does the ball hit the ground

Answer 1

The ball takes approximately 0.492 seconds to hit the ground and lands 0 meters away from the table.

Step-by-step explanation:

To calculate the time it takes for the ball to hit the ground, we can use the equation:

d = v0t + (1/2)at2

Where d is the distance, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity.

Given that the initial velocity is 0 m/s (since the ball rolls off the table without being thrown) and the acceleration due to gravity is 9.8 m/s2, we can set d to be the height of the table and solve for t. Therefore, t = sqrt((2 * d) / a). Plugging in the values, we have:

t = sqrt((2 * 1.2) / 9.8)

Calculating this, we find that it takes approximately 0.492 seconds for the ball to hit the ground.

To calculate how far from the table the ball hits the ground, we can use the equation:

d = v0t

Since the initial velocity is 0 m/s, the distance is simply the horizontal distance the ball travels. Therefore, the ball will hit the ground approximately 0 meters away from the table.

Answer 2

The ball takes approximately 0.49 seconds to hit the ground and lands approximately 0.49 meters away from the table.

Step-by-step explanation:

To calculate the time it takes for the ball to hit the ground, we can use the equation:

time = √(2 * height / acceleration due to gravity)

Using the given height of 1.2 meters and the acceleration due to gravity of 9.8 m/s², we can substitute these values into the equation to find that the time is approximately 0.49 seconds.

To calculate the distance the ball hits the ground from the table, we can use the equation:

distance = initial velocity * time

Since the ball is initially at rest, the initial velocity is 0 m/s. Substituting the time of 0.49 seconds, we find that the ball hits the ground approximately 0.49 meters away from the table.