Question

Calc II Question

Find the average value of the function on the given interval
F(x) = sin4x, [-pi, pi]


Correct answer is 45/28 but I'm not sure how to get to that answer

Answer 1

0

Explanation:

`\displaystyle (F(b)-F(a))/(b-a)\\\\=(F(\pi)-F(-\pi))/(\pi-(-\pi))\\\\=(\sin(4\pi)-\sin(-4\pi))/(2\pi)\\\\=(0-0)/(2\pi)\\\\=0`

Not sure how the correct answer is stated as 45/28, but the answer is definitely 0.