Question

Two slits are separated by a distance of 0.067 mm. A monochromatic beam of light with a

wavelength of 555 nm falls on the slits and produces an interference pattern on a screen that is 3.05 m from the slits. Calculate the fringe separation between the 2nd left and 3rd right nodal lines.

Answer 1

To calculate the fringe separation between the 2nd left and 3rd right nodal lines in the interference pattern, we need to determine the distance between these two nodal lines.

The formula to calculate the fringe separation in Young's double-slit experiment is given by:

fringe separation (Δy) = (λ * D) / d

where:
λ is the wavelength of the light (in meters)
D is the distance between the screen and the slits (in meters)
d is the distance between the two slits (in meters)

Let's convert the given values to the correct units:

λ = 555 nm = 555 * 10^(-9) m
D = 3.05 m
d = 0.067 mm = 0.067 * 10^(-3) m

Now we can calculate the fringe separation:

Δy = (λ * D) / d
= (555 * 10^(-9) * 3.05) / (0.067 * 10^(-3))
≈ 2.525 meters

Therefore, the fringe separation between the 2nd left and 3rd right nodal lines is approximately 2.525 meters.