The given equation is ェ+1=V+2. We need to approximate the solution to the nearest hundredth.
Looking at the table, we can see that as we increase the value of ェ (z), the corresponding value of V is also increasing. We are looking for the value of ェ where ェ+1 is approximately equal to V+2.
By examining the table, we can see that when ェ is around 2.5, V is around 3.50. When ェ is around 2.6, V is around 3.60. The values of V are increasing more rapidly than the values of ェ, so we know that the solution will be slightly less than 2.6.
Based on this observation, the approximate solution to the equation is:
ェ ≈ 2.6
Therefore, the correct answer is "2.6".