Question

Garage door spring has a spring constant of 800 N/m. How much will it stretch if a 200 N force is applied to it?

Answer 1

The garage door spring will stretch 0.250 m.

Step-by-step explanation:

(IMPORTANT!: Hooke's Law:
`F_(s) = -kx`)

• 
  `F_(s)` = Spring Force
• k = Spring Constant
• x = Stretch or Compression

First, isolate for x:

`x = -(F_(s) )/(k)`

Second, determine your known values:

`F_(s) = 200 N\\k = 800(N)/(m)\\x = ?`

Second, plug all known values into Hooke's equation and solve
`x = -(200 N)/(800(N)/(m) ) \\= -0.25 m`