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A panel of judges consists of 3 men and 3 women. Find the number of ways they can sit in a row if a. There are no restrictions. b. The men and the women must alternate. c. The men must sit together and the women must sit together.

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Let's calculate the number of ways the panel of judges can sit in a row for each scenario:

a. No restrictions:

In this case, we can simply calculate the total number of possible arrangements of the 6 judges in a row.

Number of ways = 6!

(6 factorial, which is 6 × 5 × 4 × 3 × 2 × 1)

Number of ways = 720

b. Men and women must alternate:

To satisfy this condition, we can fix the position of one gender (either men or women) and then arrange the other gender in the remaining positions.

Number of ways = 3! × 3!

(Number of ways to arrange the men) × (Number of ways to arrange the women)

Number of ways = 6 × 6

Number of ways = 36

c. Men must sit together and women must sit together:

In this scenario, we can treat the group of men and the group of women as single entities and arrange them in the row.

Number of ways = 2! × 3! × 3!

(Number of ways to arrange the two groups) × (Number of ways to arrange the men within their group) × (Number of ways to arrange the women within their group)

Number of ways = 2 × 6 × 6

Number of ways = 72

So, the number of ways the panel of judges can sit in a row is:

a. No restrictions: 720

b. Men and women must alternate: 36

c. Men must sit together and women must sit together: 72

answered
User Tejeshree
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