Question

A car tire has a volume of 32.2 L with a pressure of 34.5 psi when the temperature is 27°C. If the temperature increases to 43° and the volume decreases to 31.04, What is the new pressure?

Answer 1

The new pressure is 36.09 psi.

Answer 2

Using the combined gas law:

(P1 x V1) / T1 = (P2 x V2) / T2

where:

P1 = 34.5 psi (initial pressure)

V1 = 32.2 L (initial volume)

T1 = 27°C + 273.15 = 300.15 K (initial temperature in Kelvin)

V2 = 31.04 L (final volume)

T2 = 43°C + 273.15 = 316.15 K (final temperature in Kelvin)

Solving for P2:

(P1 x V1 x T2) / (V2 x T1) = P2

(34.5 psi x 32.2 L x 316.15 K) / (31.04 L x 300.15 K) = P2

P2 = 37.2 psi

Therefore, the new pressure in the tire is 37.2 psi when the temperature increases to 43°C and the volume decreases to 31.04 L.