Question

Sara and Steve each bought a pair of pants and some socks .The pants that they purchased cost the exact same amount and the pair of socks are also the same amount.

Sara paid $60 for one pair of pants and two pairs of socks

Steve paid $75 for one pair of pants and three pairs of socks

What was the cost of 1 pair of pants?

Equations

1P+2S=60

1P+3S=75

Answer 1

These are two linear equations with two unknowns, P (price of pants) and S (price of socks). You can solve them by using either substitution or elimination methods.

Let's use the elimination method.

First, let's subtract the second equation from the first:

1P + 2S - (1P + 3S) = 60 - 75

After simplifying this, we get:

-1S = -15

Dividing both sides by -1, we find:

S = 15

Now, we can substitute S = 15 into the first equation to find the price of pants (P):

1P + 2(15) = 60

1P + 30 = 60

Subtract 30 from both sides to get:

1P = 60 - 30

1P = 30

So, the price of one pair of pants (P) is $30.