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∫ x 2 −3x−28 4x−6 ​ dx=∫ (x−7)(x+4) 4x−6 ​ dx=

∫ x 2 −3x−28 4x−6 ​ dx=∫ (x−7)(x+4) 4x−6 ​ dx=
asked 44.2k views
4 votes
∫ x 2
−3x−28
4x−6
​
dx=∫ (x−7)(x+4)
4x−6
​
dx=

asked
User Crdavis
by
8.4k points

1 Answer

4 votes

Answer:

∫(−1⋅x 3

+ x 6

4

​

+ x

4

​

−2)dx

Explanation:

answered
User James Gaunt
by
9.0k points
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