Question

In the triangle above segment AC bisects <BAD

AB 13
AD 4
BC 3.5X + 8
CD 7X
solve for X

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Answer 1

According to the angle bisector theorem, AB/AD = BC/CD.

It means that 13/4 = (3.5x + 8) / 7x.

13 * 7x = (3.5x + 8) * 4

91x = 14x + 32

77x = 32

x = 32/77.