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Given ∫ −5 2 f(x)dx=−1,∫ −4 −7 f(x)dx=16 and ∫ −7 2 f(x)dx=15 a.) ∫ −4 2 f(x)dx= Tries 0/99 b.) ∫ 2 −5 Tries 0/99 f(x)dx = c.) ∫ −4 −5 f(x)dx
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Given ∫ −5 2 f(x)dx=−1,∫ −4 −7 f(x)dx=16 and ∫ −7 2 f(x)dx=15 a.) ∫ −4 2 f(x)dx= Tries 0/99 b.) ∫ 2 −5 Tries 0/99 f(x)dx = c.) ∫ −4 −5 f(x)dx
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Jul 1, 2024
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Given ∫ −5
2
f(x)dx=−1,∫ −4
−7
f(x)dx=16 and ∫ −7
2
f(x)dx=15 a.) ∫ −4
2
f(x)dx= Tries 0/99 b.) ∫ 2
−5
Tries 0/99 f(x)dx
= c.) ∫ −4
−5
f(x)dx
Mathematics
high-school
Lukmo
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Answer:
Explanation:
∫ x 2
−3x−28
4x−6
dx=∫ (x−7)(x+4)
4x−6
dx=
Ttomsen
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Jul 8, 2024
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Ttomsen
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