Answer:
C. sin(L) = JK/JL = MN/LN
Explanation:
You want the ratios representing the sine of one of the acute angles in the given pair of similar triangles.
Trig ratios
The trig ratio for the sine of an angle in a right triangle is ...
Sin = Opposite/Hypotenuse
Application
For angle J, the sine relations are ...
sin(J) = KM/JN = KL/JL = LM/LN
For angle L, the sine relations are ...
sin(L) = JK/JL = MN/LN . . . . . . . . . . . . matches choice C
__
Additional comment
The short segments JN and KM are proportional in length to the longer segments of which they are a part (JL and KL, respectively). This is why they can be used in the sine relation for angle J.
<95141404393>