Question

A region in the plane is bounded by the x-axis, the graph y=16-x^2 and the lines x=0 and x= 3. Compute the area of the region enclosed under the graph

Answer 1

39

Explanation:

`\displaystyle A=\int^3_0(16-x^2)dx=16x-(x^3)/(3)\biggr|^3_0=16(3)-(3^3)/(3)=48-(27)/(3)=48-9=39`