Question

Need help on this thanks I’ll give points

Answer 1

t=
`-(2log 2 (3))/(3)`

Explanation:

`52^(-3t)`=45

Use the rules of exponents and logarithms to solve the equation.

5*
`2^(-3t)`=45

Divide both sides by 5.

2^-3t=9

Take the logarithm of both sides of the equation.

log(2-^3t)=log(9)

The logarithm of a number raised to a power is the power times the logarithm of the number.

-3t log(2)=log(9)

Divide both sides by log(2).

-3t =
`(log(9))/(log(2))`

By the change-of-base formula

-3t=
`log_(2)` (9)

Divide both sides by −3

t=
`-(2log 2 (3))/(3)`