asked 16.6k views
0 votes
Given the function h(x)=-x^2+x+4, determine the average rate of change of the function over the interval −6≤x≤4.

asked
User Stine
by
8.0k points

1 Answer

7 votes
The average rate of change of a function over an interval is given by the formula:

Average rate of change = (f(b) - f(a)) / (b - a)

where a and b are the endpoints of the interval.

In this case, the interval is −6≤x≤4, so a = -6 and b = 4. The function is h(x)=-x^2+x+4, so:

h(-6) = -(-6)^2 + (-6) + 4 = -20
h(4) = -(4)^2 + (4) + 4 = -8

Therefore, the average rate of change of h(x) over the interval −6≤x≤4 is:

Average rate of change = (h(4) - h(-6)) / (4 - (-6))
= (-8 - (-20)) / (4 + 6)
= 12 / 10
= 1.2

So the average rate of change of the function over this interval is 1.2.
answered
User Modesitt
by
7.3k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.