Question

44 points if someone gets it right.

You roll a six-sided one time. After that, you spin a spinner that is equally divided into 6 parts. 1 part is red, 2 parts are pink, and 3 parts are blue.

What is the probability of rolling a number less than 5 and then the spinner stopping at a blue section.

Answer 1

Therefore, the probability of rolling a number less than 5 and the spinner stopping at a blue section is 1/3.

Explanation:

To calculate the probability of rolling a number less than 5 and then the spinner stopping at a blue section, we need to determine the individual probabilities and multiply them together.

First, let's calculate the probability of rolling a number less than 5. Since the die is six-sided, there are four numbers (1, 2, 3, 4) that satisfy this condition. The total number of possible outcomes is 6.

So, the probability of rolling a number less than 5 is 4/6, which simplifies to 2/3.

Next, let's calculate the probability of the spinner stopping at a blue section. The spinner has a total of 6 sections, with 3 of them being blue. Therefore, the probability of the spinner stopping at a blue section is 3/6, which simplifies to 1/2.

To find the probability of both events occurring, we multiply the probabilities:

Probability = Probability of rolling a number less than 5 * Probability of spinner stopping at a blue section

Probability = (2/3) * (1/2)

Probability = 2/6

Probability = 1/3

Therefore, the probability of rolling a number less than 5 and the spinner stopping at a blue section is 1/3.