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A 6.6 kg object undergoes an acceleration of 3.9 m/s2.

What is the magnitude of the resultant force acting on it?
If this same force is applied to a 4.0 kg object, what acceleration is produced?

1 Answer

3 votes

Answer:

6.435 m/s^2.

Explanation:

To find the magnitude of the resultant force acting on the 6.6 kg object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given:

Mass of the object (m) = 6.6 kg

Acceleration (a) = 3.9 m/s^2

Using the formula:

Force (F) = m * a

Substituting the given values:

F = 6.6 kg * 3.9 m/s^2

F = 25.74 N (rounded to two decimal places)

Therefore, the magnitude of the resultant force acting on the 6.6 kg object is approximately 25.74 N.

Now, if the same force is applied to a 4.0 kg object, we can use the same formula to find the acceleration produced.

Given:

Mass of the object (m) = 4.0 kg

Force (F) = 25.74 N (as calculated above)

Using the formula:

F = m * a

Rearranging the formula to solve for acceleration:

a = F / m

Substituting the given values:

a = 25.74 N / 4.0 kg

a = 6.435 m/s^2 (rounded to three decimal places)

Therefore, the acceleration produced when the same force is applied to a 4.0 kg object is approximately 6.435 m/s^2.

answered
User Adam Hawes
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