Question

21 points if someone gets it right.

You randomly pull a scrap from a bag of scraps. The bag has 3 red scraps, 4 yellow scraps, and 4 black scraps. After that, you roll a number cube one time

What is the probability of drawing a black scrap then rolling two.

Answer 1

Explanation:

11 scraps .... 4 are black

chance of a black scrap = 4/11

roll die.... 6 possible outcomes one is a '2'

one out of six = 1/6

4/11 * 1/6 = 4/66 = 2/33 = .061

Answer 2

Answer: P(black scrap and rolling 2) = 6.06%

Explanation:

We will divide the wanted outcome by the total number of possible outcomes from both scenarios.

`\displaystyle \frac{\text{wanted outcome}}{\text{possible outcomes}} =(4\;black\;scraps)/(11\;total\;scraps)=(4)/(11)`

`\displaystyle \frac{\text{wanted outcome}}{\text{possible outcomes}} =\frac{\text{rolling a 2}}{\text{six sides on a number cube}}=(1)/(6)`

Next, to find the compounded probability, we will multiply these two fractions by each other, divide, and multiply by 100 to create a percentage.

`\displaystyle (4)/(11) *(1)/(6) =(4*1)/(11*6)=(4)/(66) \approx 0.06060606`

`0.06060606 * 100 = 6.06\%`