Question

In the figure we have an electric circuit made up of identical resistors with = 2 Ω.

The equivalent resistance between points A and B is:
a.)2 Ω
b.)1,25 Ω
c.)1,75 Ω
d.)2,25 Ω

Answer 1

To determine the equivalent resistance between points A and B in the given electric circuit, we need to analyze the arrangement of resistors.

In the figure, it appears that the resistors are arranged in a series-parallel combination. The resistors R1 and R2 are connected in series, while the combination of R3 and R4 is connected in parallel. Let's calculate the equivalent resistance step by step:

1. The resistors R1 and R2 are in series, so we can add their resistances:

R1 + R2 = 2 Ω + 2 Ω = 4 Ω

2. The combination of R3 and R4 is in parallel, so we can calculate their equivalent resistance using the formula:

1/Req = 1/R3 + 1/R4

Substituting the values:

1/Req = 1/2 Ω + 1/2 Ω = 2/2 Ω = 1 Ω

Taking the reciprocal of both sides:

Req = 1/1 Ω = 1 Ω

3. The resistors R1+R2 and Req are in series, so we can add their resistances:

R_total = (R1 + R2) + Req = 4 Ω + 1 Ω = 5 Ω

Therefore, the equivalent resistance between points A and B is 5 Ω.

None of the given options (a.) 2 Ω, b.) 1.25 Ω, c.) 1.75 Ω, d.) 2.25 Ω) matches the calculated value of 5 Ω.