Question

Please help using sine, cosine, tangent

Answer 1

Explanation:

3a.)

sin(a)=12/13

cos(a)=5/13

tan(a)=12/5

3b.)

sin(b)=3/5

cos(b)=4/5

tan(b)=3/4

I guess you could write arc_(number/number) instead of what i currently have. For example, instead of tan(a)=12/5 you can write a=arctan(12/5). obviously, they're equal, so you could probably go either way.

4a.)

cos(a)= 38/47

a=arccos(38/47)

a=36.0493290536= 36

4b.)

sin(a)=19/35

a=arcsin(19/35)

a=32.8783495644 = 32.9