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Answer:
T = 2 Π (L/g)^1/2 period of simple pendlim
T = K L^12 variation of period with length
dT = 1/2 K L^-1/2 dL
dT / T = 1 / ( 2 L) dL
dL / L = 2 dT / T = 2 * 8.3 / (60 * 60 * 24) = 1.92E-4
If L = 1 m then dL = .192 mm