Question

10. How many grams are in 6.25 x1023 of BaC₂N₂?

a.1222.3
b.800.23
C.196.15
d.900.45

Answer 1

Option C

To determine the number of grams in a given number of molecules, we need to calculate the molar mass of the compound.

The molar mass of BaC₂N₂ can be calculated as follows:
(1 atom of Ba) + (2 atoms of C) + (2 atoms of N) = 137.33 g/mol + 2(12.01 g/mol) + 2(14.01 g/mol) = 137.33 g/mol + 24.02 g/mol + 28.02 g/mol = 189.37 g/mol

Now, we can calculate the number of grams in 6.25 x 10^23 molecules of BaC₂N₂:

6.25 x 10^23 molecules x (189.37 g/mol / 6.022 x 10^23 molecules/mol) ≈ 197.15 g

Therefore, the answer is approximately 197.15 grams. So, option C. 196.15 is the correct choice.