Question

4) An amusement park ride has a radius of 2.8 m. If the time of one revolution of a rider is 0.98 s, what is the speed of the rider

Answer 1

17.959

Step-by-step explanation:

v = 2πr/T

v = 2 x 22 x 2.8/ 7 x 0.98

v = 123.2/ 6.86

v = 17.9

Answer 2

The speed of the rider on the amusement park ride is 17.94 m/s.

Step-by-step explanation:

To calculate the speed of the rider on the amusement park ride, we can use the formula for linear speed, which is the circumference of the circular path divided by the time taken for one revolution. The circumference of the circular path is 2π times the radius, so the speed of the rider can be calculated as:

Speed = 2π(radius) / time

Plugging in the given values:

Speed = 2π(2.8 m) / 0.98 s = 17.94 m/s

Therefore, the speed of the rider on the amusement park ride is approximately 17.94 m/s.