asked 95.2k views
4 votes
What is the concentration (M) of a solution containing 29 grams of salt (NaCl) dissolved in 0.4 Liters of water?

Round your answer to the nearest hundredth (2 decimal places). Do NOT include units.

asked
User Lamorak
by
8.8k points

1 Answer

5 votes

Step by step calculation:

Given:

Mass of NaCl = 29 grams

Volume of solution = 0.4 Liters

Molar mass of NaCl = 58.44 g/mol

Calculate number of moles of NaCl:

moles = mass/molar mass

moles = 29g / 58.44 g/mol

= 0.496 moles

Concentration (M) = moles / liters of solution

Concentration = 0.496 moles / 0.4 L

= 1.24 M

Since the answer is to be rounded to the nearest hundredth, the final concentration is:

1.24

answered
User Hamed MP
by
7.7k points

No related questions found