Question

In the disaster movie, Airport 77, Flight 23 has crashed in the Bermuda Triangle and sinks to a depth of 73 meters below the ocean surface. What would be the approximate seawater pressure on the plane at these depths

Answer 1

The seawater pressure on the plane at 73 meters depth would be approximately 734425 N/m² or 734 kPa.

Step-by-step explanation:

The pressure exerted by seawater at a certain depth can be calculated using the formula Pressure (P) = density (ρ) × gravitational acceleration (g) × depth (h). To find the approximate seawater pressure on the plane at a depth of 73 meters, we use the density of seawater, which is approximately 1025 kg/m³, and the gravitational acceleration, which is approximately 9.8 m/s². Thus, the pressure P can be calculated as follows:

P = ρ × g × h
P = 1025 kg/m³ × 9.8 m/s² × 73 m
P = 734425 N/m²

Therefore, the approximate pressure on the plane would be 734425 N/m² or approximately 734 kPa, considering the ambient atmospheric pressure is added to the absolute pressure.

Answer 2

Answer: 106.28 PSI

Step-by-step explanation:

Or 7.33 BAR

Each meter is approximately 0.1 BAR (very, very roughly)