Question

A student performed sequential transfers of one milliliter portions of a liquid into a 50 mL beaker. The masses recorded are as follows: Mass of beaker: 26.4750 g Mass after first transfer: 27.4850 g Mass after second transfer: 28.5000 g Mass after third transfer: 29.5160 g Answer the following questions using the given data. Calculate the mass of each portion of the liquid and the mean mass of a portion of the liquid.

Answer 1

Explanation:To calculate the mass of each portion of the liquid, we need to subtract the mass of the empty beaker from the mass of the beaker with the liquid after each transfer.

Mass of first portion of liquid = 27.4850 g - 26.4750 g = 1.0100 g

Mass of second portion of liquid = 28.5000 g - 27.4850 g = 1.0150 g

Mass of third portion of liquid = 29.5160 g - 28.5000 g = 1.0160 g

To calculate the mean mass of a portion of the liquid, we need to take the average of the masses of the three portions of the liquid.

Mean mass of a portion of the liquid = (1.0100 g + 1.0150 g + 1.0160 g)/3 = 1.0133 g

Therefore, the mass of each portion of the liquid is 1.0100 g, 1.0150 g, and 1.0160 g, and the mean mass of a portion of the liquid is 1.0133 g.