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The sliding carton skids onto a rough surface and stops in 3 s. Calculate the force of friction it encounters.

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User Pantera
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1 Answer

3 votes

Final answer:

The force of friction encountered by the sliding carton on the rough surface is zero. In order to determine the force of friction acting on a sliding carton, Newton's second law of motion is employed.

Step-by-step explanation:

In order to determine the force of friction acting on a sliding carton, Newton's second law of motion is employed, expressing force as the product of mass and acceleration.

In this scenario, the carton comes to a stop within 3 seconds, allowing the calculation of acceleration using the formula a = 2*(displacement)/(time^2).

Since the carton's displacement is 0 (as it stops), the acceleration is also 0.

Substituting the carton's mass into the force formula, force = mass * acceleration, results in force = mass * 0, leading to a force of friction encountered by the carton equal to zero.

This conclusion arises from the absence of acceleration due to the carton's coming to a halt, indicating a lack of net external forces acting on it during the deceleration process.

answered
User Grant Limberg
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7.5k points
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