Question

If a 633 nmnm laser shines through a slide and produces a pattern on a screen 24.0 cmcm distant, what range of sizes of the central maximum should be expected

Answer 1

The question requires knowledge of wave optics and the interference pattern caused by diffraction in a double-slit experiment, to estimate the size of the central maximum on a screen.

Step-by-step explanation:

The question concerns the interference pattern produced by a laser light passing through a slide and the characteristics of the central maximum observed on the screen. This is a typical high school physics problem involving the concepts of wave optics, diffraction, and the double-slit experiment.

To estimate the size of the central maximum, we would need to use the double-slit interference equation ∆y = λL / d, where ∆y is the distance between adjacent fringes on the screen, λ is the wavelength of the laser light, L is the distance from the slits to the screen, and d is the distance between the slits. However, since the question does not provide the distance between the slits (d), we cannot calculate an exact size for the central maximum. In general, though, one could expect the central maximum to be the brightest and widest part of the pattern, and it usually spans several orders of fringe on either side.

Answer 2

The range of sizes of the central maximum depends on the size of the aperture used in the slide.

Step-by-step explanation:

The central maximum refers to the bright central region in patterns formed by interference or diffraction. In this case, a 633 nm laser is shining through a slide and producing a pattern on a screen 24.0 cm away. The range of sizes of the central maximum depends on the size of the aperture used in the slide.

If we assume a single slit aperture, the size of the central maximum can be determined by the formula:

Central Maximum Size = λ * distance / aperture size

Where:

• λ is the wavelength of the laser (633 nm)
• distance is the distance between the slide and the screen (24.0 cm)

Note that the aperture size is not given in the question, so we cannot calculate the exact range of sizes of the central maximum without that information.