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Hi guys, I have math questions that are hard to solve. Can anyone help?The first question:Sarah is 20 yrs older than her sis, Sarahs bro is 12 yrs younger than sarahs sisA) write an equation for this situation and her siblings relationshipB) if her bro is 1 year old find the other variableSecond question:The total number of students in the seventhgrade is 9 more than 4 times as many studentsas are in the art class. There are 101 students inthe seventh grade. Write and solve an equationto find the number of students in the art class. Let x represent the number of students in theart class. PLS HELP

1 Answer

3 votes

Answer:

First question

(A)

If As represent Sarah's age, B represents her sister's age, and C represents her brother's age, the expression we get for the relationship between their ages is A - 20 = B = C + 12

(B)

If her brother is 1, her sister is 13, and she is 33.

Second question

Equation: 101 = 9+4x

Answer: 23 art class students

Explanation:

First question

(A)

Let A represent Sarah's age, B represent her sister's age, and C represent her brother's age.

We are told Sarah is 20 yrs older than her sister: A - 20 = B

We are told Sarah's brother is 12 yrs younger than Sarah's sister: C +12 = B

Combining these two equations, we get: A - 20 = B = C + 12

(B)

If her brother is one year old, then C = 1.

B = C + 12 = 1 +12 =13

A - 20 = B, A = B+20=13+20=33

So if her brother is 1, her sister is 13, and she is 33.

Second question

We are told that the total number of students in the seventh grade is 9 more than 4 times as many students as there are in the art class. Write this out as an expression bit by bit to solve.

"4 times as many students as there are in the art class": 4X

"9 more than 4 times as many students as there are in the art class": 9 + 4X

"The total number of students in the seventh grade (101) is 9 more than 4 times as many students as there are in the art class": 101= 9 +4X

Solve this to fins the number of art class students:

101=9+4X

92=4x

x=23

answered
User Xavier Haniquaut
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