Answer:
The probability is: 1/55
Explanation:
The first sock you pick must be one of the two matching ones.
There are 2 matching socks out of 11, and all others are different.
First pick: p(one of the 2 matching socks) = 2/11
Now there are 10 socks left, and only one of them matches the first pick.
Second pick: p(the other matching sock) = 1/10
p(both matching socks) = 2/11 × 1/10 = 2/110 = 1/55